If N_2,O_2,H_2,and He are filled in four sepa | vedclass

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(C) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ of a gas is inversely proportional to the square root of its molar mass $(M)$:

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$H_2$

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(C) According to Graham's Law of Diffusion,the rate of diffusion $(r)$ of a gas is inversely proportional to the square root of its molar mass $(M)$: $r \propto \frac{1}{\sqrt{M}}$.Comparing the molar masses: $M(H_2) = 2 \ g/mol$,$M(He) = 4 \ g/mol$,$M(N_2) = 28 \ g/mol$,and $M(O_2) = 32 \ g/mol$.Since $H_2$ has the lowest molar mass,it will have the highest rate of diffusion.Therefore,$H_2$ will leak out first.

If $N_2$,$O_2$,$H_2$,and $He$ are filled in four separate car tubes at the same pressure,which one will leak out first?

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