If 500 mL of gas A at 1000 torr and 1000 m | vedclass

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(B) Using Boyle's Law,$P_1V_1 = P_2V_2$ at constant temperature.For gas $A$: $1000 \ torr 	imes 500 \ mL = P_A 	imes 2000 \ mL$. So,$P_A = (1000 	i

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$650$

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(B) Using Boyle's Law,$P_1V_1 = P_2V_2$ at constant temperature.For gas $A$: $1000 \ torr 	imes 500 \ mL = P_A 	imes 2000 \ mL$. So,$P_A = (1000 	imes 500) / 2000 = 250 \ torr$.For gas $B$: $800 \ torr 	imes 1000 \ mL = P_B 	imes 2000 \ mL$. So,$P_B = (800 	imes 1000) / 2000 = 400 \ torr$.According to Dalton's Law of partial pressures,the total pressure $P_{total} = P_A + P_B$.$P_{total} = 250 \ torr + 400 \ torr = 650 \ torr$.

If $500 \ mL$ of gas $A$ at $1000 \ torr$ and $1000 \ mL$ of gas $B$ at $800 \ torr$ are taken in a $2 \ L$ container,the final pressure is .......... $torr$.

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