Under which conditions does the van der Waa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The $van \ der \ Waals$ equation for $n$ moles of a gas is given by: $(P + \frac{an^2}{V^2})(V - nb) = nRT$. For $1$ mole of gas,it is $(P + \frac

Vedclass · Accepted Answer

Low pressure and high temperature

Vedclass · Answer

(C) The $van \ der \ Waals$ equation for $n$ moles of a gas is given by: $(P + \frac{an^2}{V^2})(V - nb) = nRT$. For $1$ mole of gas,it is $(P + \frac{a}{V_m^2})(V_m - b) = RT$. At low pressure,the volume $V_m$ is very large,so $b$ becomes negligible compared to $V_m$. At high temperature,the pressure $P$ is significant compared to the internal pressure term $\frac{a}{V_m^2}$,making $\frac{a}{V_m^2}$ negligible. Thus,the equation reduces to $PV_m = RT$,which is the ideal gas equation.

Under which conditions does the $van \ der \ Waals$ equation reduce to the ideal gas equation?

Similar Questions

What is the reason for the deviation of pressure from ideal behavior?

Explain real gases showing deviations from ideal gas with correction of pressure and volume and derive van der Waals equation.

Under which conditions do intermolecular forces become effective?

Under which conditions does a gas show the greatest deviation from the ideal gas equation $PV = nRT$?

For real gases,the relation between $P$,$V$ and $T$ is given by the van der Waals equation,$(P + \frac{an^2}{V^2})(V - nb) = nRT$. For the following gases $CH_4, CO_2, O_2, H_2$,which gas will have $(i)$ highest value of $'a'$ $(ii)$ lowest value of $'b'$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module