The density of a gas at -23 ^oC temperature | vedclass

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(D) Using the ideal gas equation in terms of density: $d = \frac{PM_w}{RT}$ Given: $P = \frac{780}{760} \ atm$,$T = -23 + 273 = 250 \ K$,$d = 1.40 \ g

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$N_2$

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(D) Using the ideal gas equation in terms of density: $d = \frac{PM_w}{RT}$ Given: $P = \frac{780}{760} \ atm$,$T = -23 + 273 = 250 \ K$,$d = 1.40 \ g/L$,$R = 0.0821 \ L \cdot atm \cdot K^{-1} \cdot mol^{-1}$ Substituting the values: $1.40 = \frac{(\frac{780}{760}) 	imes M_w}{0.0821 	imes 250}$ $M_w = \frac{1.40 	imes 0.0821 	imes 250 	imes 760}{780} \approx 28 \ g/mol$ The molar mass of $N_2$ is $28 \ g/mol$. Therefore,the gas is $N_2$.

The density of a gas at $-23 \ ^oC$ temperature and $780 \ \text{torr}$ pressure is $1.40 \ g/L$. Identify the gas.

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