A gas occupies 10 L at STP. Which of the fol | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the ideal gas law,$PV = nRT$. Since the amount of gas $(n)$ is constant,the relationship is $\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

Vedclass · Accepted Answer

$273 \ ^oC$ and $2 \ atm$

Vedclass · Answer

(B) According to the ideal gas law,$PV = nRT$. Since the amount of gas $(n)$ is constant,the relationship is $\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$.At $STP$,$P_1 = 1 \ atm$,$T_1 = 273 \ K$,and $V_1 = 10 \ L$.We want $V_2 = 10 \ L$,so the condition $\frac{P_1}{T_1} = \frac{P_2}{T_2}$ must be satisfied.For option $A$: $\frac{1}{273} 
eq \frac{2}{273}$.For option $B$: $T_2 = 273 + 273 = 546 \ K$. $\frac{P_2}{T_2} = \frac{2}{546} = \frac{1}{273}$. This matches the initial condition.Therefore,option $B$ is correct.

$A$ gas occupies $10 \ L$ at $STP$. Which of the following conditions will result in the same volume?

Similar Questions

At a given temperature,the density of an ideal gas is proportional to $(P = \text{pressure of ideal gas})$

Explain: Gay-Lussac's Law.

Which of the following equations is true for $8.8 \times 10^{-2} \ kg$ of carbon dioxide gas?

At very low pressure,the compressibility factor $Z$ of a $CO_2$ gas with constant molar volume is:

Which one of the following is the correct $PV$ vs $P$ plot at constant temperature for an ideal gas? ($P$ and $V$ stand for pressure and volume of the gas respectively)

Vedclass Test Series

Exam Paper Generator

Online Exam Module