The unit of the Van der Waals constant 'a' is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The Van der Waals equation for real gases is given by: $(P + \frac{an^2}{V^2})(V - nb) = nRT$. From the term $\frac{an^2}{V^2}$,which is added to

Vedclass · Accepted Answer

$atm\,L^2\,mol^{-2}$

Vedclass · Answer

(A) The Van der Waals equation for real gases is given by: $(P + \frac{an^2}{V^2})(V - nb) = nRT$. From the term $\frac{an^2}{V^2}$,which is added to pressure $(P)$,the units of $\frac{an^2}{V^2}$ must be the same as the units of pressure $(atm)$. Therefore,$unit(a) = unit(P) 	imes \frac{unit(V)^2}{unit(n)^2}$. Substituting the units: $unit(a) = atm 	imes \frac{L^2}{mol^2} = atm\,L^2\,mol^{-2}$.

The unit of the Van der Waals constant '$a$' is .......

Similar Questions

Gases deviate from ideal gas behavior because the molecules $...$

When $He$ gas is expanded into a vacuum,a heating effect is observed. What is the reason for this?

At low pressure,Vander Waal's equation is reduced to $\left[ P + \frac{a}{V^2} \right]V = RT$. The compressibility factor $(Z)$ can be given as

Under which conditions do intermolecular forces become effective?

Van der Waals equation for a gas is stated as,
$p = \frac{nRT}{V - nb} - a\left( \frac{n}{V} \right)^2$
This equation reduces to the perfect gas equation,$p = \frac{nRT}{V}$,when:

Vedclass Test Series

Exam Paper Generator

Online Exam Module