For an ideal gas,the compressibility factor $(Z)$ is equal to:

If $2.5$ moles of an ideal gas at a certain temperature are allowed to expand isothermally and reversibly from an initial volume of $2$ $dm^3$ to $20$ $dm^3$, the work done by the gas is $-16.5$ $kJ$. The temperature (in $K$) of the gas is (Round off to the nearest value). $(R = 8.314 \ J \ K^{-1} \ mol^{-1})$

At $300 \ K$ temperature and $1 \ atm$ pressure,the weight of $1 \ L$ of a gas is $2 \ g$. If the pressure is changed to $0.75 \ atm$,at what temperature in $K$ will the weight of $1 \ L$ of the same gas be $1 \ g$?

The temperature of $1 \, mol$ of a gas is increased by $2 \, ^oC$ at constant pressure. The work done will be:

One litre of a gas weighs $2 \ g$ at $300 \ K$ and $1 \ atm$ pressure. If the pressure is made $0.75 \ atm$,at which of the following temperatures will one litre of the same gas weigh $1 \ g$?

When the temperature of a flask with a capacity of $1 \ L$ is increased from $25 \ ^oC$ to $35 \ ^oC$,calculate the volume of air in $mL$ that escapes from the flask.