NaCl is doped with 2 times 10^{-3} , mol % , | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) When $SrCl_2$ is added to $NaCl$,each $Sr^{2+}$ ion replaces two $Na^+$ ions to maintain electrical neutrality.One $Sr^{2+}$ ion creates one catio

Vedclass · Accepted Answer

$12.04 	imes 10^{18} \, mol^{-1}$

Vedclass · Answer

(B) When $SrCl_2$ is added to $NaCl$,each $Sr^{2+}$ ion replaces two $Na^+$ ions to maintain electrical neutrality.One $Sr^{2+}$ ion creates one cation vacancy.Concentration of $SrCl_2 = 2 	imes 10^{-3} \, mol \% = \frac{2 	imes 10^{-3}}{100} = 2 	imes 10^{-5} \, mol$ per $100 \, mol$ of $NaCl$.Number of cation vacancies per mole of $NaCl = 2 	imes 10^{-5} 	imes N_A$.$= 2 	imes 10^{-5} 	imes 6.022 	imes 10^{23} \, mol^{-1}$.$= 12.044 	imes 10^{18} \, mol^{-1}$.

$NaCl$ is doped with $2 \times 10^{-3} \, mol \% \, SrCl_2$. What is the concentration of cation vacancies?

Similar Questions

Explain Schottky defect and Frenkel defect.

Schottky defect defines imperfection in the lattice structure of a

Calculate the percentage of $Fe^{+2}$ in $Fe_{0.95}O$.

The appearance of colour in solid alkali metal halides is generally due to

Electron-deficient impurities are caused by the elements of which group?

Vedclass Test Series

Exam Paper Generator

Online Exam Module