If a gas diffuses 1/5 times as fast as hydrog | vedclass

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(A) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $r_1/r_2 = \s

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$50$

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(A) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molar mass $M$: $r_1/r_2 = \sqrt{M_2/M_1}$.Given that the rate of the gas $r_g = (1/5) 	imes r_{H_2}$,we have $r_{H_2}/r_g = 5$.Substituting this into the formula: $\sqrt{M_g/M_{H_2}} = 5$.Squaring both sides: $M_g/M_{H_2} = 25$.Since the molar mass of hydrogen $M_{H_2} = 2 \ g/mol$,we get $M_g = 25 	imes 2 = 50 \ g/mol$.

If a gas diffuses $1/5$ times as fast as hydrogen,its molar mass will be....

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