The rms velocity of hydrogen is sqrt{7} times | vedclass

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(C) The formula for $rms$ velocity is $v_{rms} = \sqrt{\frac{3RT}{M}}$.Given $v_{rms(H_2)} = \sqrt{7} 	imes v_{rms(N_2)}$.Substituting the formula: $

Vedclass · Accepted Answer

$T_{(H_2)} < T_{(N_2)}$

Vedclass · Answer

(C) The formula for $rms$ velocity is $v_{rms} = \sqrt{\frac{3RT}{M}}$.Given $v_{rms(H_2)} = \sqrt{7} 	imes v_{rms(N_2)}$.Substituting the formula: $\sqrt{\frac{3RT_{H_2}}{M_{H_2}}} = \sqrt{7} 	imes \sqrt{\frac{3RT_{N_2}}{M_{N_2}}}$.Squaring both sides: $\frac{3RT_{H_2}}{M_{H_2}} = 7 	imes \frac{3RT_{N_2}}{M_{N_2}}$.Given $M_{H_2} = 2 \ g/mol$ and $M_{N_2} = 28 \ g/mol$.$\frac{T_{H_2}}{2} = 7 	imes \frac{T_{N_2}}{28}$.$\frac{T_{H_2}}{2} = \frac{T_{N_2}}{4}$.$T_{H_2} = \frac{T_{N_2}}{2}$.Therefore,$T_{(H_2)} < T_{(N_2)}$.

The $rms$ velocity of hydrogen is $\sqrt{7}$ times the $rms$ velocity of nitrogen. If the temperature of the gas is $T$,then which of the following is true?

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