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In $H$ atom,an orbit has a diameter of about $16.92 \ \mathring{A}$. What is the maximum number of electrons that can be accommodated in this orbit?

Given below are two statements:
Statement $I$: Rutherford's gold foil experiment cannot explain the line spectrum of hydrogen atom.
Statement $II$: Bohr's model of hydrogen atom contradicts Heisenberg's uncertainty principle.
In the light of the above statements,choose the most appropriate answer from the options given below:

Match the following columns:
Column-$I$ Column-$II$
$(1)$ Photon $(A)$ Value of $4$ for $N$ shell
$(2)$ Electron $(B)$ Probability density
$(3)$ $\psi^2$ $(C)$ Always $+$ value
$(4)$ Principal quantum number $(n)$ $(D)$ Represents wavelength and momentum

Match the following items:
$A$. Energy of ground state of $He^+$$i$. $+6.04 \text{ eV}$
$B$. Potential energy of $I$ orbit of $H$ atom$ii$. $-27.2 \text{ eV}$
$C$. Kinetic energy of $II$ excited state of $He^+$$iii$. $8.72 \times 10^{-18} \text{ J}$
$D$. Ionization potential of $He^+$$iv$. $-54.4 \text{ eV}$

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For the given electronic transitions,which of the following statements is correct?

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