The 39^{th} electron of an element enters whi | vedclass

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(B) To determine the subshell of the $39^{th}$ electron,we write the electronic configuration of the element with atomic number $Z = 39$ (Yttrium).The

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$4d$

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(B) To determine the subshell of the $39^{th}$ electron,we write the electronic configuration of the element with atomic number $Z = 39$ (Yttrium).The order of filling orbitals according to the Aufbau principle is: $1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, \dots$The configuration is: $1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^2, 3d^{10}, 4p^6, 5s^2, 4d^1$.The total number of electrons is $2+2+6+2+6+2+10+6+2+1 = 39$.The $39^{th}$ electron enters the $4d$ subshell.

The $39^{th}$ electron of an element enters which of the following subshells?

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