The correct form of the $Schrodinger$ wave equation for an electron,as derived by $Erwin$ $Schrodinger$,is:

  • A
    $\frac{d^2\Psi}{dx^2} + \frac{d^2\Psi}{dy^2} + \frac{d^2\Psi}{dz^2} + \frac{8\pi m}{h^2}(V - E)\Psi = 0$
  • B
    $\frac{d^2\Psi}{dx^2} + \frac{d^2\Psi}{dy^2} + \frac{d^2\Psi}{dz^2} + \frac{8\pi^2 m}{h^2}(E - V)\Psi = 0$
  • C
    $\frac{d^2\Psi}{dx^2} + \frac{d^2\Psi}{dy^2} + \frac{d^2\Psi}{dz^2} + \frac{8\pi^2 m}{h^2}(V - E)\Psi = 0$
  • D
    $\frac{d^2\Psi}{dx^2} + \frac{d^2\Psi}{dy^2} + \frac{d^2\Psi}{dz^2} + \frac{8\pi^2 m}{h}(E - V)\Psi = 0$

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Similar Questions

Uncertainty in the position of an electron (mass $= 9.1 \times 10^{-31} \ kg$) moving with a velocity $300 \ ms^{-1}$ accurate up to $0.001 \ \%$ will be $(h = 6.63 \times 10^{-34} \ J \cdot s)$.

"The position and velocity of a small particle like an electron cannot be simultaneously determined." This statement is:

Find the uncertainty in the position of an electron which is moving with a velocity of $2.99 \times 10^4 \ cm \ s^{-1}$,accurate up to $0.0016 \%$. (Given,$m_e = 9.1 \times 10^{-28} \ g, h = 6.626 \times 10^{-27} \ erg \cdot s$)

The uncertainties in the velocities of two particles,$A$ and $B$ are $0.05 \ ms^{-1}$ and $0.02 \ ms^{-1}$ respectively. The mass of $B$ is five times that of the mass of $A$. What is the ratio of uncertainties $\frac{\Delta x_A}{\Delta x_B}$ in their positions?

The uncertainty of velocity of an electron is $5.7 \times 10^5 \ m \ s^{-1}$. Find its uncertainty in position.

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