The atomic number of the element (in ground s | vedclass

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Question

(A) The electronic configuration of the given elements in their ground state is as follows:$1.$ For atomic number $8$ $(O)$: $1s^2 2s^2 2p^4$. Number

Vedclass · Accepted Answer

$15$

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(A) The electronic configuration of the given elements in their ground state is as follows:$1.$ For atomic number $8$ $(O)$: $1s^2 2s^2 2p^4$. Number of unpaired $3p$ electrons = $0$.$2.$ For atomic number $10$ $(Ne)$: $1s^2 2s^2 2p^6$. Number of unpaired $3p$ electrons = $0$.$3.$ For atomic number $12$ $(Mg)$: $1s^2 2s^2 2p^6 3s^2$. Number of unpaired $3p$ electrons = $0$.$4.$ For atomic number $15$ $(P)$: $1s^2 2s^2 2p^6 3s^2 3p^3$. The $3p$ subshell has $3$ orbitals,each containing $1$ unpaired electron according to Hund's rule.Thus,the element with atomic number $15$ has the maximum number of unpaired $3p$ electrons ($3$ unpaired electrons).

The atomic number of the element (in ground state) having the maximum number of unpaired $3p$ electrons is:

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