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(C) The electronic configuration of an element with the outermost orbital $4s^2$ implies that the $3d$ subshell is completely filled. Following the Au

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$30$

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(C) The electronic configuration of an element with the outermost orbital $4s^2$ implies that the $3d$ subshell is completely filled. Following the Aufbau principle,the complete electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2$. Summing the electrons: $2 + 2 + 6 + 2 + 6 + 10 + 2 = 30$. Therefore,the atomic number is $30$,which corresponds to Zinc $(Zn)$.

An element has an outermost orbital configuration of $4s^2$. What is its atomic number?

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