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Question

(D) Given energy $E = 2 \ eV = 2 	imes 1.602 	imes 10^{-19} \ J = 3.204 	imes 10^{-19} \ J$.For wavelength $(\lambda)$: $E = \frac{hc}{\lambda} \im

Vedclass · Accepted Answer

$6.204 	imes 10^{-7} \ m, 4.8 	imes 10^{14} \ s^{-1}$

Vedclass · Answer

(D) Given energy $E = 2 \ eV = 2 	imes 1.602 	imes 10^{-19} \ J = 3.204 	imes 10^{-19} \ J$.For wavelength $(\lambda)$: $E = \frac{hc}{\lambda} \implies \lambda = \frac{hc}{E}$.$\lambda = \frac{6.626 	imes 10^{-34} \ J \cdot s 	imes 3 	imes 10^8 \ m \cdot s^{-1}}{3.204 	imes 10^{-19} \ J} = 6.204 	imes 10^{-7} \ m$.For frequency $(
u)$: $
u = \frac{c}{\lambda} = \frac{3 	imes 10^8 \ m \cdot s^{-1}}{6.204 	imes 10^{-7} \ m} = 0.4835 	imes 10^{15} \ s^{-1} \approx 4.8 	imes 10^{14} \ s^{-1}$.

The wavelength and frequency of a photon with energy $2 \ eV$ are respectively:

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