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(A) The energy of an orbital in a multi-electron atom depends on the effective nuclear charge $(Z_{eff})$.As the atomic number $(Z)$ increases,the att

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$E_{2s(H)} > E_{2s(Li)} > E_{2s(Na)} > E_{2s(K)}$

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(A) The energy of an orbital in a multi-electron atom depends on the effective nuclear charge $(Z_{eff})$.As the atomic number $(Z)$ increases,the attraction between the nucleus and the electrons increases,which lowers the energy of the orbital.For the $2s$-orbital,the energy decreases as the nuclear charge increases.The atomic numbers are $H (Z=1)$,$Li (Z=3)$,$Na (Z=11)$,and $K (Z=19)$.Since $Z_{eff}$ increases from $H$ to $K$,the energy of the $2s$-orbital decreases in the order: $E_{2s(H)} > E_{2s(Li)} > E_{2s(Na)} > E_{2s(K)}$.

What is the decreasing order of energy for the $2s$-orbital of $H, Li, Na$,and $K$ atoms?

Similar Questions

The quantum numbers $n = 2, l = 1$ represent:

Arrange the energy of the $2s$ orbital in the following atoms in decreasing order: $H, Li, Na, K$.

The quantum numbers of four electrons are given below:
$I. \ n = 4, l = 2, m_l = -2, m_s = -1/2$
$II. \ n = 3, l = 2, m_l = 1, m_s = +1/2$
$III. \ n = 4, l = 1, m_l = 0, m_s = +1/2$
$IV. \ n = 3, l = 1, m_l = 1, m_s = -1/2$
The correct order of their increasing energies will be:

Which of the following represents the ground state electronic configuration of an atom?

Which of the following orbitals has the least energy?

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