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(D) The nucleus of $_6C^{12}$ consists of $6$ protons and $6$ neutrons. Electrons are located outside the nucleus,so doubling their mass does not affe

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It will decrease by $25\%$.

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(D) The nucleus of $_6C^{12}$ consists of $6$ protons and $6$ neutrons. Electrons are located outside the nucleus,so doubling their mass does not affect the mass of the nucleus.Initially,the mass of the nucleus is $6 	imes m_p + 6 	imes m_n \approx 12 	ext{ amu}$.If the mass of each neutron is halved $(m_n' = 0.5 	imes m_n)$,the new mass of the nucleus becomes $6 	imes m_p + 6 	imes (0.5 	imes m_n) = 6 	imes m_p + 3 	imes m_n$.Since $m_p \approx m_n$,the initial mass is $12$ units and the new mass is $9$ units.The decrease in mass is $12 - 9 = 3$ units.Percentage decrease = $(3 / 12) 	imes 100\% = 25\%$.

An atom is composed of protons,neutrons,and electrons. If the mass of a neutron is halved and the mass of an electron is doubled,what will be the change in the mass of the nucleus of $_6C^{12}$?

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