The maximum number of electrons with principa | vedclass

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Question

(D) For a given principal quantum number $n$,the total number of orbitals is given by $n^2$.For $n = 3$,the total number of orbitals is $3^2 = 9$.Each

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(D) For a given principal quantum number $n$,the total number of orbitals is given by $n^2$.For $n = 3$,the total number of orbitals is $3^2 = 9$.Each orbital can hold a maximum of two electrons,one with $m_s = +1/2$ and one with $m_s = -1/2$.Therefore,the number of electrons with $m_s = -1/2$ is equal to the total number of orbitals,which is $9$.

The maximum number of electrons with principal quantum number $n = 3$ and spin quantum number $m_s = -1/2$ is:

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