Calculate the wavelength of an electron if its mass is $9.1 \times 10^{-31} \, kg$,its velocity is $1/10$ of the speed of light,and the value of Planck's constant $h$ is $6.626 \times 10^{-34} \, J \cdot s$.

  • A
    $2.446 \times 10^{-7} \, m$
  • B
    $2.246 \times 10^{-9} \, m$
  • C
    $2.426 \times 10^{-11} \, m$
  • D
    $2.246 \times 10^{-13} \, m$

Explore More

Similar Questions

The de Broglie wavelength of a car of mass $1000 \ kg$ and velocity $36 \ km/hr$ is

The basis of the quantum mechanical model of an atom is:

According to the wave-particle duality of matter by de-Broglie,which of the following graph plots presents the most appropriate relationship between the wavelength of an electron $(\lambda)$ and the momentum of an electron $(p)$?

In the ground state of a hydrogen atom,an electron absorbs $1.5$ times the minimum energy $\left(2.18 \times 10^{-18} \ J\right)$ required to escape from the atom. The wavelength of the emitted electron (in $m$) is $\left(m_e = 9 \times 10^{-31} \ kg\right)$.

The wavelength associated with a particle of mass $9.109 \times 10^{-31} \ kg$ moving with a velocity of $1.20 \times 10^5 \ m/s$ is ....... meters.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo