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(D) The energy of a photon is given by the formula $E = h
u = \frac{hc}{\lambda}$.Since $h$ and $c$ are constants,$E \propto \frac{1}{\lambda}$.There

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$2$

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(D) The energy of a photon is given by the formula $E = h
u = \frac{hc}{\lambda}$.Since $h$ and $c$ are constants,$E \propto \frac{1}{\lambda}$.Therefore,the ratio of energies is $\frac{E_1}{E_2} = \frac{\lambda_2}{\lambda_1}$.Given $\lambda_1 = 2000 \ \mathring{A}$ and $\lambda_2 = 4000 \ \mathring{A}$.Substituting the values,we get $\frac{E_1}{E_2} = \frac{4000}{2000} = 2$.

List-$I$	List-$II$
$(1)$ $X$-rays	$(A)$ $\nu = 10^0 - 10^4 \ Hz$
$(2)$ Ultraviolet $(UV)$ rays	$(B)$ $\nu = 10^{10} \ Hz$
$(3)$ Long radio waves	$(C)$ $\nu = 10^{16} \ Hz$
$(4)$ Microwave	$(D)$ $\nu = 10^{18} \ Hz$

What is the ratio of the energy of photons having wavelengths $2000 \ \mathring{A}$ and $4000 \ \mathring{A}$?

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