A neutral atom has 2, 8, and 7 electrons in i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The electronic configuration of the atom based on the given shell distribution $(K=2, L=8, M=7)$ is as follows:$K$ shell $(n=1)$: $1s^2$ (contains

Vedclass · Accepted Answer

$11$

Vedclass · Answer

(D) The electronic configuration of the atom based on the given shell distribution $(K=2, L=8, M=7)$ is as follows:$K$ shell $(n=1)$: $1s^2$ (contains $2$ electrons)$L$ shell $(n=2)$: $2s^2 2p^6$ (contains $8$ electrons)$M$ shell $(n=3)$: $3s^2 3p^5$ (contains $7$ electrons)Total electrons in $p$-orbitals = (electrons in $2p$) + (electrons in $3p$)Total = $6 + 5 = 11$ electrons.Therefore,the correct option is $D$.

$A$ neutral atom has $2, 8,$ and $7$ electrons in its $K, L,$ and $M$ shells,respectively. What is the total number of electrons in the $p$-orbitals?

Similar Questions

Which one of the statements regarding quantum numbers is false?

Which one is the correct outer electronic configuration of chromium $(Cr)$?

Write the increasing order of energy for $2p, 3p, 4p, 5p$ orbitals.

Which two factors affect the energy of an electron in an orbit? How?

According to which principle is the electronic configuration of nitrogen $1s^2 2s^2 2p_x^1 2p_y^1 2p_z^1$ and not $1s^2 2s^2 2p_x^2 2p_y^1 2p_z^0$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module