The ratio of the radii of the 3^{rd} and 5^{t | vedclass

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(A) The radius of an orbit is given by the formula: $r_n = 0.529 	imes \frac{n^2}{Z} \ \mathring{A}$.For $He^+$,the atomic number $Z = 2$.For the $3^

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$9 : 25$

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(A) The radius of an orbit is given by the formula: $r_n = 0.529 	imes \frac{n^2}{Z} \ \mathring{A}$.For $He^+$,the atomic number $Z = 2$.For the $3^{rd}$ orbit $(n = 3)$: $r_3 = 0.529 	imes \frac{3^2}{2} = 0.529 	imes \frac{9}{2} \ \mathring{A}$.For the $5^{th}$ orbit $(n = 5)$: $r_5 = 0.529 	imes \frac{5^2}{2} = 0.529 	imes \frac{25}{2} \ \mathring{A}$.The ratio $\frac{r_3}{r_5} = \frac{0.529 	imes \frac{9}{2}}{0.529 	imes \frac{25}{2}} = \frac{9}{25}$.Therefore,the ratio is $9 : 25$.

The ratio of the radii of the $3^{rd}$ and $5^{th}$ orbits of $He^+$ is ..... . (Atomic number of $He = 2$,$r = 0.529 \times \frac{n^2}{Z} \ \mathring{A}$)

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