The number of valence electrons in Fe^{2+} io | vedclass

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Question

(A) The atomic number of $Fe$ is $26$. The electronic configuration of neutral $Fe$ is $[Ar] 3d^6 4s^2$.When $Fe$ forms an $Fe^{2+}$ ion,it loses two

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$6$

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(A) The atomic number of $Fe$ is $26$. The electronic configuration of neutral $Fe$ is $[Ar] 3d^6 4s^2$.When $Fe$ forms an $Fe^{2+}$ ion,it loses two electrons from the outermost $4s$ orbital.Thus,the electronic configuration of $Fe^{2+}$ becomes $[Ar] 3d^6$.The valence electrons are the electrons in the outermost shell or the partially filled $d$-subshell involved in bonding. For $Fe^{2+}$,the $3d$ electrons are considered valence electrons. There are $6$ electrons in the $3d$ subshell.

The number of valence electrons in $Fe^{2+}$ ion $(Fe = 26)$ is .......

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