When the uncertainty in the position of a moving particle is $0$,then the uncertainty in momentum $(p)$ is equal to:

The uncertainty in the position of an electron is $1 \, \mathring{A}$. Find the uncertainty in its velocity.

If the uncertainty in momentum of a particle is twice the uncertainty in its position,what will be the uncertainty in the position of the particle?

The uncertainties in the velocities of particles $A$ and $B$ are $0.05 \, m/s$ and $0.02 \, m/s$,respectively. If the mass of particle $B$ is five times that of particle $A$,then the ratio of the uncertainties in their positions $\left( \frac{\Delta x_A}{\Delta x_B} \right)$ is equal to:

The wave mechanical model of atom is based upon

Calculate the mass of an elementary particle,which is accelerated to twice the velocity of light with the precision $\pm 1 \%$,and has $1.05 \times 10^{-13} \ m$ uncertainty in position. $(h = 6.6 \times 10^{-34} \ kg \ m^2 \ s^{-1})$