If the velocities of hydrogen (H_2) and heliu | vedclass

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(B) According to the de Broglie wavelength formula,$\lambda = \frac{h}{mv}$.Since the velocity $(v)$ and Planck's constant $(h)$ are constant,$\lambda

Vedclass · Accepted Answer

$1:2$

Vedclass · Answer

(B) According to the de Broglie wavelength formula,$\lambda = \frac{h}{mv}$.Since the velocity $(v)$ and Planck's constant $(h)$ are constant,$\lambda \propto \frac{1}{m}$.Therefore,$\frac{\lambda_{He}}{\lambda_{H_2}} = \frac{m_{H_2}}{m_{He}}$.The molar mass of $H_2$ is $2 \ g/mol$ and the molar mass of $He$ is $4 \ g/mol$.Substituting the values: $\frac{\lambda_{He}}{\lambda_{H_2}} = \frac{2}{4} = \frac{1}{2}$.Thus,the ratio is $1:2$.

If the velocities of hydrogen $(H_2)$ and helium $(He)$ molecules are equal,then the ratio of the wavelengths of helium to hydrogen is .......

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