For Li^{2+},the ratio of radii r_2 : r_5 is: | vedclass

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(B) The radius of an orbit in a hydrogen-like species is given by the formula: $r_n = a_0 	imes \frac{n^2}{Z}$,where $a_0$ is the Bohr radius,$n$ is

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$4 : 25$

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(B) The radius of an orbit in a hydrogen-like species is given by the formula: $r_n = a_0 	imes \frac{n^2}{Z}$,where $a_0$ is the Bohr radius,$n$ is the principal quantum number,and $Z$ is the atomic number.For $Li^{2+}$,$Z = 3$.The ratio of radii for $n = 2$ and $n = 5$ is:$\frac{r_2}{r_5} = \frac{n_2^2 / Z}{n_5^2 / Z} = \frac{n_2^2}{n_5^2} = \frac{2^2}{5^2} = \frac{4}{25}$.Thus,the ratio $r_2 : r_5$ is $4 : 25$.

For $Li^{2+}$,the ratio of radii $r_2 : r_5$ is:

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