(B) The given rate law is $\text{Rate} = K[A]^2[B]$.When a reactant is taken in large excess,its concentration remains effectively constant throughout

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) The given rate law is $\text{Rate} = K[A]^2[B]$.When a reactant is taken in large excess,its concentration remains effectively constant throughout the reaction.Since $[A]$ is in large excess,$[A] \approx \text{constant}$.Therefore,the rate law becomes $\text{Rate} = K' [B]$,where $K' = K[A]^2$.This is a pseudo-first-order reaction.Thus,the order of the reaction with respect to $[B]$ is $1$.

Class 12 Chemistry Chemical Kinetics Rate law , Rate constant , Order of Reaction and Molecularity

Medium

For the reaction $A + 2B \rightarrow \text{Product } (P)$,the rate law is given by $\frac{d[P]}{dt} = K[A]^2[B]$. If $[A]$ is taken in large excess,what will be the order of the reaction?

A
$0$
B
$1$
C
$2$
D
$3$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Chemical Kinetics

Subtopic

Rate law , Rate constant , Order of Reaction and Molecularity

The reaction $2NO + O_2 \rightarrow 2NO_2$ is an example of which order of reaction?

Easy

View Solution

For which type of reactions,order and molecularity have the same value?

Easy

View Solution

If the order of the reaction $x + y \xrightarrow{hv} xy$ is zero,it means that the rate of

Medium

View Solution

For a certain reaction,the rate $= k[A]^2[B]$. When the initial concentration of $A$ is tripled keeping the concentration of $B$ constant,the initial rate would:

MediumNEET 2023

View Solution

For the chemical reaction $2A + 2B + C \rightarrow \text{Product}$,the rate law is given by $r \propto [A] [B]^2$. What is the order of the reaction?

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

For the reaction $A + 2B \rightarrow \text{Product } (P)$,the rate law is given by $\frac{d[P]}{dt} = K[A]^2[B]$. If $[A]$ is taken in large excess,what will be the order of the reaction?

Similar Questions

The reaction $2NO + O_2 \rightarrow 2NO_2$ is an example of which order of reaction?

For which type of reactions,order and molecularity have the same value?

If the order of the reaction $x + y \xrightarrow{hv} xy$ is zero,it means that the rate of

For a certain reaction,the rate $= k[A]^2[B]$. When the initial concentration of $A$ is tripled keeping the concentration of $B$ constant,the initial rate would:

For the chemical reaction $2A + 2B + C \rightarrow \text{Product}$,the rate law is given by $r \propto [A] [B]^2$. What is the order of the reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module