For a reaction between substances $A$ and $B$,the rate law is given by: $\text{Rate} = K[A]^n[B]^m$. If the concentration of $A$ is doubled and the concentration of $B$ is halved,what will be the ratio of the new rate to the original rate?

  • A
    $2^{\frac{1}{n+m}}$
  • B
    $m+n$
  • C
    $2^{n-m}$
  • D
    $n-m$

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