The $K_{sp}$ value of $AgCl$ at $25^{\circ}C$ is $1.8 \times 10^{-10}$. If $10^{-5} \ mol$ of $Ag^{+}$ is added to the solution,the new $K_{sp}$ value will be:

  • A
    $1.8 \times 10^{-15}$
  • B
    $1.8 \times 10^{-10}$
  • C
    $1.8 \times 10^{-5}$
  • D
    $1.8 \times 10^{-20}$

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