Match List-I (Equilibrium) with List-II (Cond | vedclass

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(C) According to Le Chatelier's principle:$1$. For endothermic reactions $(\Delta H > 0)$,high temperature favors the forward reaction.$2$. For exothe

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$(P-1 \& \ 5), (Q-2 \& \ 3), (R-1 \& \ 4)$

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(C) According to Le Chatelier's principle:$1$. For endothermic reactions $(\Delta H > 0)$,high temperature favors the forward reaction.$2$. For exothermic reactions $(\Delta H $3$. For reactions where $\Delta n_g = 0$,the equilibrium is independent of pressure.Analysis:$P: A_{2(g)}   B_{2(g)} \rightleftharpoons 2AB_{(g)}$ (Endothermic,$\Delta n_g = 0$). Favored by high temperature $(1)$ and is independent of pressure $(5)$.$Q: 2AB_{2(g)}   B_{2(g)} \rightleftharpoons 2AB_{3(g)}$ (Exothermic,$\Delta n_g = -1$). Favored by low temperature $(2)$.$R: 2AB_{3(g)} \rightleftharpoons A_{2(g)}   3B_{2(g)}$ (Endothermic,$\Delta n_g =  2$). Favored by high temperature $(3)$.Matching: $P-(1, 5), Q-(2), R-(3)$.Correct option is $C$.

List-$I$ (Equilibrium)	List-$II$ (Conditions for the process)
$P. A_{2(g)} + B_{2(g)} \rightleftharpoons 2AB_{(g)}$ (Endothermic)	$1. \text{High temperature}$
$Q. 2AB_{2(g)} + B_{2(g)} \rightleftharpoons 2AB_{3(g)}$ (Exothermic)	$2. \text{Low temperature}$
$R. 2AB_{3(g)} \rightleftharpoons A_{2(g)} + 3B_{2(g)}$ (Endothermic)	$3. \text{High temperature}$
	$4. \text{Low temperature}$
	$5. \text{Independent of pressure}$

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