Find the concentration of hydrogen ions in a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formula for $pH$ is given by: $pH = -\log[H^+]$Given $pH = 5.4$,we have: $5.4 = -\log[H^+]$Therefore,$\log[H^+] = -5.4$To find $[H^+]$,we take

Vedclass · Accepted Answer

$3.98 	imes 10^{-6}$

Vedclass · Answer

(C) The formula for $pH$ is given by: $pH = -\log[H^+]$Given $pH = 5.4$,we have: $5.4 = -\log[H^+]$Therefore,$\log[H^+] = -5.4$To find $[H^+]$,we take the antilog: $[H^+] = 	ext{antilog}(-5.4)$$[H^+] = 	ext{antilog}(-6 + 0.6)$$[H^+] = 10^{-6} 	imes 	ext{antilog}(0.6)$Since $	ext{antilog}(0.6) \approx 3.98$,we get:$[H^+] = 3.98 	imes 10^{-6} \ mol/L$

Find the concentration of hydrogen ions in a solution with $pH = 5.4$ in $mol/L$.

Similar Questions

The $pH$ of rain water is approximately

Pure water does not conduct electricity because ....

The $pH$ of $D_2O$ and $H_2O$ at $298 \ K$ is

If $20 \ mL$ of an acidic solution of $pH$ $3$ is diluted to $100 \ mL$,the $H^{+}$ ion concentration will be

If the ionic product of water $(K_w)$ is $1.96 \times 10^{-14}$ at $35^{\circ} C$, what is its value at $10^{\circ} C$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module