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(A) The dissociation of $Na_2SO_4$ is given by: $Na_2SO_4(s) \rightleftharpoons 2Na^+(aq) + SO_4^{2-}(aq)$.Let the solubility be $s \ mol/L$. Then,$[N

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$5 	imes 10^{-16}$

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(A) The dissociation of $Na_2SO_4$ is given by: $Na_2SO_4(s) ightleftharpoons 2Na^+(aq) + SO_4^{2-}(aq)$.Let the solubility be $s \ mol/L$. Then,$[Na^+] = 2s$ and $[SO_4^{2-}] = s$.Given that $[Na^+] = 10^{-5} \ mol/L$,we have $2s = 10^{-5}$,so $s = 0.5 	imes 10^{-5} \ mol/L$.The solubility product expression is $K_{sp} = [Na^+]^2 [SO_4^{2-}] = (2s)^2(s) = 4s^3$.Substituting the value of $s$: $K_{sp} = 4 	imes (0.5 	imes 10^{-5})^3$.$K_{sp} = 4 	imes 0.125 	imes 10^{-15} = 0.5 	imes 10^{-15} = 5 	imes 10^{-16}$.

If the concentration of sodium ions in a saturated solution of $Na_2SO_4$ is $10^{-5} \ mol/L$,find the solubility product $(K_{sp})$.

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