The degree of hydrolysis of a N/100 KCN solut | vedclass

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(B) For the salt of a weak acid and strong base,the degree of hydrolysis $(h)$ is given by the formula: $h = \sqrt{\frac{K_w}{K_a 	imes C}}$Given: $K

Vedclass · Accepted Answer

$2.7 	imes 10^{-2}$

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(B) For the salt of a weak acid and strong base,the degree of hydrolysis $(h)$ is given by the formula: $h = \sqrt{\frac{K_w}{K_a 	imes C}}$Given: $K_w = 10^{-14}$,$K_a = 1.4 	imes 10^{-9}$,and $C = 1/100 = 10^{-2} \ M$.Substituting the values: $h = \sqrt{\frac{10^{-14}}{1.4 	imes 10^{-9} 	imes 10^{-2}}}$$h = \sqrt{\frac{10^{-14}}{1.4 	imes 10^{-11}}} = \sqrt{\frac{10^{-3}}{1.4}} = \sqrt{0.714 	imes 10^{-3}} = \sqrt{7.14 	imes 10^{-4}}$$h \approx 2.67 	imes 10^{-2} \approx 2.7 	imes 10^{-2}$.

The degree of hydrolysis of a $N/100$ $KCN$ solution is = ....... (Given $K_a = 1.4 \times 10^{-9}$)

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