For the reaction PCl_5 rightleftharpoons PCl_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For the reaction $PCl_5 \rightleftharpoons PCl_3 + Cl_2$,the degree of dissociation $\alpha$ is given by $\alpha \propto \frac{1}{\sqrt{P}}$.Since

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) For the reaction $PCl_5 \rightleftharpoons PCl_3 + Cl_2$,the degree of dissociation $\alpha$ is given by $\alpha \propto \frac{1}{\sqrt{P}}$.Since $PV = nRT$,at constant temperature,$P \propto \frac{1}{V}$.Substituting this into the relation,we get $\alpha \propto \sqrt{V}$.Given that the volume increases to $16$ times the initial volume $(V_2 = 16V_1)$,the new degree of dissociation $\alpha_2$ is:$\frac{\alpha_2}{\alpha_1} = \sqrt{\frac{V_2}{V_1}} = \sqrt{\frac{16V_1}{V_1}} = \sqrt{16} = 4$.Therefore,the degree of dissociation becomes $4$ times the initial value.

Similar Questions

The degree of dissociation of a weak acid is $7.2 \times 10^{-4}$. What is the value of its percent dissociation in a $0.025 \ M$ solution (in $\%$)?

If $PCl_{5(g)}$ is $40\%$ dissociated at equilibrium at $27\,^{\circ}C$ and $1\, atm$,then calculate the density of the equilibrium mixture at $27\,^{\circ}C$ and $1\, atm$ for the reaction: $PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$ (in $g\,L^{-1}$)

If $D_T$ and $D_0$ are the theoretical and observed vapour densities at a definite temperature and $\alpha$ is the degree of dissociation of a substance,then $\alpha$ in terms of $D_0, D_T$ and $n$ (number of moles of product formed from $1 \, \text{mole}$ of reactant) is calculated by the formula:

In a closed vessel,the dissociation of phosphorus pentachloride occurs as: $PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)$. If the total pressure at equilibrium is $P$ and the degree of dissociation of $PCl_5$ is $x$,then the partial pressure of $PCl_3$ will be:

What is the vapour density of $O_2$ gas?

Vedclass Test Series

Exam Paper Generator

Online Exam Module