The correct order of basicity is........

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(C) To determine the basicity,we look at the conjugate acids of the given species: $1$. The conjugate acid of $H_2O$ is $H_3O^+$. $2$. The conjugate a

Vedclass · Accepted Answer

$H_2O < CH_3OH < OH^{-} < CH_3O^{-}$

Vedclass · Answer

(C) To determine the basicity,we look at the conjugate acids of the given species: $1$. The conjugate acid of $H_2O$ is $H_3O^+$. $2$. The conjugate acid of $OH^-$ is $H_2O$. $3$. The conjugate acid of $CH_3OH$ is $CH_3OH_2^+$. $4$. The conjugate acid of $CH_3O^-$ is $CH_3OH$. Stronger acids have weaker conjugate bases. The acidity order of the conjugate acids is $CH_3OH_2^+ > H_3O^+ > CH_3OH > H_2O$. Therefore,the basicity order is the reverse: $H_2O $CH_3O^-$ is a stronger base than $OH^-$ due to the electron-donating inductive effect $(+I)$ of the methyl group,which increases the electron density on the oxygen atom.

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