For the reversible reaction $A + B \rightleftharpoons C + D$,the equilibrium concentrations of $C$ and $D$ are $0.8 \ mol/L$ each. If the initial concentrations of $A$ and $B$ were $1 \ mol/L$ each,calculate the equilibrium constant $K_c$.

  • A
    $6.4$
  • B
    $0.64$
  • C
    $1.6$
  • D
    $16$

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$(b)$ $2NH_{3(g)} \rightleftharpoons N_{2(g)} + 3H_{2(g)}$
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At $527 \ ^oC$,the reaction given below has $K_c = 4$.
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