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(B) The given relation is $\frac{K_p}{K_c} + \log(RT) = 0$,which can be rewritten as $\log(\frac{K_p}{K_c}) = -\log(RT) = \log((RT)^{-1})$.Taking the

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$2SO_2 + O_2 \rightleftharpoons 2SO_3$

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(B) The given relation is $\frac{K_p}{K_c} + \log(RT) = 0$,which can be rewritten as $\log(\frac{K_p}{K_c}) = -\log(RT) = \log((RT)^{-1})$.Taking the antilog,we get $\frac{K_p}{K_c} = (RT)^{-1}$,which implies $K_p = K_c(RT)^{-1}$.Comparing this with the standard relation $K_p = K_c(RT)^{\Delta n}$,we find that $\Delta n = -1$.For option $A$: $\Delta n = (1+1) - 1 = 1$.For option $B$: $\Delta n = 2 - (2+1) = -1$.For option $C$: $\Delta n = 2 - (1+3) = -2$.Thus,the reaction in option $B$ satisfies the condition $\Delta n = -1$.

For which of the following reactions is the relation $\frac{K_p}{K_c} + \log(RT) = 0$ correct?

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