The solubility product of $Mg(OH)_2$ is $9 \times 10^{-12}$. If the concentration of $Mg^{+2}$ is $0.01 \ M$,then the concentration of $OH^{-}$ is = .....

  • A
    $9 \times 10^{-10}$
  • B
    $3 \times 10^{-5}$
  • C
    $9 \times 10^{-12}$
  • D
    $3 \times 10^{-7}$

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