The solubility product $(K_{sp})$ of $AgCl$ at $100 \, ^\circ C$ is $1.44 \times 10^{-4}$. The solubility of $AgCl$ in boiling water is $.......$

  • A
    $0.72 \times 10^{-4} \, M$
  • B
    $1.20 \times 10^{-2} \, M$
  • C
    $0.72 \times 10^{-2} \, M$
  • D
    $1.20 \times 10^{-4} \, M$

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