During the titration of $N/10$ acetic acid with $N/10 \, NaOH$,what is the $pH$ of the solution when $25\%$,$50\%$,and $75\%$ of the titration is complete? $[K_a = 10^{-5}]$

  • A
    $5 + \log(1/3), 5, 5 + \log(3)$
  • B
    $5 + \log(3), 4, 5 + \log(1/3)$
  • C
    $5 - \log(1/3), 5, 5 - \log(3)$
  • D
    $5 - \log(1/3), 4, 5 + \log(1/3)$

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$50 \, mL$ of $0.1 \, M \, CH_3COOH$ is being titrated against $0.1 \, M \, NaOH$. When $25 \, mL$ of $NaOH$ has been added,the $pH$ of the solution will be $.... \times 10^{-2}$. (Nearest integer)
(Given : $pK_a(CH_3COOH) = 4.76$)
$\log 2 = 0.30$,$\log 3 = 0.48$,$\log 5 = 0.69$,$\log 7 = 0.84$,$\log 11 = 1.04$

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