The $K_{sp}$ of $AgBr$ at $25 \, ^\circ C$ is $4.9 \times 10^{-13}$. If the molar mass of $AgBr$ is $188 \, g/mol$,how much $AgBr$ is required to saturate $20 \, L$ of water?

  • A
    $7 \times 10^{-7} \times 188$
  • B
    $14 \times 10^{-6} \times 188$
  • C
    $14 \times 10^{7} \times 188$
  • D
    $7 \times 10^{-7} \times (188)^{-1}$

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