How many grams of CaC_2O_4 will dissolve in d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The dissociation of $CaC_2O_4$ is given by: $CaC_2O_4(s) \rightleftharpoons Ca^{2+}(aq) + C_2O_4^{2-}(aq)$.Let the solubility be $s \, mol \, L^{-

Vedclass · Accepted Answer

$0.0064$

Vedclass · Answer

(A) The dissociation of $CaC_2O_4$ is given by: $CaC_2O_4(s) ightleftharpoons Ca^{2+}(aq) + C_2O_4^{2-}(aq)$.Let the solubility be $s \, mol \, L^{-1}$.Then,$K_{sp} = [Ca^{2+}][C_2O_4^{2-}] = s 	imes s = s^2$.Given $K_{sp} = 2.5 	imes 10^{-9}$.So,$s = \sqrt{2.5 	imes 10^{-9}} = \sqrt{25 	imes 10^{-10}} = 5 	imes 10^{-5} \, mol \, L^{-1}$.Mass of $CaC_2O_4$ dissolved in $1 \, L$ = $s 	imes 	ext{Molar Mass} = 5 	imes 10^{-5} \, mol \, L^{-1} 	imes 128 \, g \, mol^{-1} = 640 	imes 10^{-5} \, g = 0.0064 \, g$.

How many grams of $CaC_2O_4$ will dissolve in distilled water to make $1 \, L$ of a saturated solution (in $, g$)? The solubility product $(K_{sp})$ of $CaC_2O_4$ is $2.5 \times 10^{-9} \, mol^2 \, L^{-2}$ and its molar mass is $128 \, g \, mol^{-1}$.

Similar Questions

The solubility of $AgCN$ in a buffer solution of $pH = 3$ is $x$. The value of $x$ is [Assume : No cyano complex is formed; $K_{sp}(AgCN) = 2.2 \times 10^{-16}$ and $K_{a}(HCN) = 6.2 \times 10^{-10}$]

The relationship between solubility $(S)$ and solubility product $(K_{sp})$ for a salt of type $A_x B_y$ is given by:

The solubility of $CaCO_3$ in water is $3.05 \times 10^{-4} \, mol/L$. Its solubility product will be:

If the solubility products of $AgBrO_3$ and $Ag_2SO_4$ are $5.5 \times 10^{-5}$ and $2 \times 10^{-5}$ respectively,what is the relationship between their solubilities?

The solubility product of salt $B_2A$ is $3.2 \times 10^{-11}$ at $298 \ K$. What is the solubility of the salt at the same temperature?

Vedclass Test Series

Exam Paper Generator

Online Exam Module