The solubility product of $AgCl$ at $25 \, ^\circ C$ is $5 \times 10^{-13}$. Its solubility is = .......

  • A
    $5 \times 10^{-13}$
  • B
    $7.1 \times 10^{-7}$
  • C
    $2.5 \times 10^{-13}$
  • D
    $2.5 \times 10^{-6}$

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