For the reaction 2SO_2(g) + O_2(g) rightlefth | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given reaction is $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$ with $\Delta H^o = -198 \, kJ$.Since $\Delta H^o < 0$,the reaction is exothe

Vedclass · Accepted Answer

Decrease in temperature and increase in pressure

Vedclass · Answer

(A) The given reaction is $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$ with $\Delta H^o = -198 \, kJ$.Since $\Delta H^o According to Le Chatelier's principle,for an exothermic reaction,a decrease in temperature favors the forward reaction.For the pressure effect,we look at the change in the number of moles of gas: $\Delta n_g = 2 - (2 + 1) = -1$.Since the number of moles decreases in the forward direction,an increase in pressure favors the forward reaction.Therefore,the favorable conditions are a decrease in temperature and an increase in pressure.

For the reaction $2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)$,$\Delta H^o = -198 \, kJ$. According to Le Chatelier's principle,the favorable conditions for the forward reaction are:

Similar Questions

For the reaction $PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$,the forward reaction at constant temperature is favoured by

Consider the reaction $HCN_{(aq)} \Leftrightarrow H_{(aq)}^{+} + CN_{(aq)}^{-}$. At equilibrium,the addition of $CN_{(aq)}^{-}$ would

What is the effect of increasing pressure on the dissociation of $PCl_5$ according to the equation $PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)} - x \ cal$?

The reaction $CaCO_3 \rightleftharpoons CaO + CO_{2(g)}$ goes to completion in a lime kiln because:

Explain the effect of temperature on equilibrium using a suitable experiment.

Vedclass Test Series

Exam Paper Generator

Online Exam Module