If the solubility of $MX_2$ in water is $0.0002 \ mol/L$,then its $K_{sp}$ is:

  • A
    $3.2 \times 10^{-11}$
  • B
    $1.16 \times 10^{-11}$
  • C
    $0.8 \times 10^{-11}$
  • D
    $0.32$

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The solubility product of $BaCl_2$ is $4 \times 10^{-9}$. Its solubility in $mol/L$ is .......

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