A force of 10 N is applied on an object of m | vedclass

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Question

(B) According to the Work-Energy Theorem,the work done by the net force on an object is equal to the change in its kinetic energy.Work done $(W)$ = Fo

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(B) According to the Work-Energy Theorem,the work done by the net force on an object is equal to the change in its kinetic energy.Work done $(W)$ = Force $(F)$ $	imes$ Displacement $(s)$.Given: $F = 10 \ N$,$s = 1 \ m$.$W = 10 \ N 	imes 1 \ m = 10 \ J$.Since the object starts from rest (implied),the change in kinetic energy is equal to the work done.Therefore,the kinetic energy gained = $10 \ J$.

$A$ force of $10 \ N$ is applied on an object of mass $2 \ kg$ over a distance of $1 \ m$. What will be the kinetic energy gained by the object in $J$?

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