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(A) Given that the body starts from rest $(u = 0)$ and attains velocity $v$ in time $T$ with uniform acceleration $a$.Using the equation of motion $v

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$\frac{mv^2}{T^2} t$

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(A) Given that the body starts from rest $(u = 0)$ and attains velocity $v$ in time $T$ with uniform acceleration $a$.Using the equation of motion $v = u + at$,we get $v = 0 + aT$,which implies $a = \frac{v}{T}$.At any time $t$,the velocity of the body is $v(t) = at = \left( \frac{v}{T} \right) t$.The force acting on the body is $F = ma = m \left( \frac{v}{T} \right)$.Instantaneous power $P$ is given by the product of force and velocity: $P = F \cdot v(t)$.Substituting the values: $P = \left( m \frac{v}{T} \right) \left( \frac{v}{T} t \right) = \frac{mv^2}{T^2} t$.

$A$ body of mass $m$ starts from rest and moves with uniform acceleration such that it attains a velocity $v$ in time $T$. The instantaneous power delivered to the body as a function of time $t$ is given by:

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