$A$ pump is used to lift $7200 \ kg$ of water per hour from a depth of $100 \ m$. Calculate the power of the pump in $kW$. Assume its efficiency is $50\%$.

$A$ block of mass $50 \,kg$ is pulled with a constant speed of $4 \,ms^{-1}$ across a horizontal floor by an applied force of $500 \,N$ directed $30^{\circ}$ above the horizontal. The rate at which the force does work on the block in watt is

$A$ body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time $t$ is proportional to

$A$ bead of mass $400 \ g$ is moving along a straight line under a force that delivers a constant power $1.2 \ W$ to the bead. If the bead is initially at rest,the speed it attains after $6 \ s$ in $m \ s^{-1}$ is:

From an automatic gun,a man fires $360$ bullets per minute with a speed of $360 \ km/h$. If each bullet weighs $20 \ g$,the power of the gun is $...... \ W$.

The power of a water pump is $2 \; kW$. If we take $g = 10 \; m/s^2$, how many liters of water can be raised to a height of $10 \; m$ in one minute?