(C) The loss in kinetic energy during a perfectly inelastic collision is given by the formula: $\Delta K = \frac{1}{2} \left( \frac{m_1 m_2}{m_1 + m_2

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(C) The loss in kinetic energy during a perfectly inelastic collision is given by the formula: $\Delta K = \frac{1}{2} \left( \frac{m_1 m_2}{m_1 + m_2} \right) (u_1 - u_2)^2$. Given: $m_1 = 40 \ kg$,$u_1 = 4 \ m/s$,$m_2 = 60 \ kg$,$u_2 = 2 \ m/s$. Substituting the values: $\Delta K = \frac{1}{2} \left( \frac{40 \times 60}{40 + 60} \right) (4 - 2)^2$. $\Delta K = \frac{1}{2} \left( \frac{2400}{100} \right) (2)^2$. $\Delta K = \frac{1}{2} \times 24 \times 4$. $\Delta K = 12 \times 4 = 48 \ J$.

Class 11 Physics Work, Energy, Power and Collision Perfectly Inelastic Collision

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$A$ scooter of mass $40 \ kg$ moving with a velocity of $4 \ m/s$ collides with another scooter of mass $60 \ kg$ moving with a velocity of $2 \ m/s$. After the collision,both scooters stick together. Find the loss in kinetic energy in $J$.

A
$392$
B
$440$
C
$48$
D
$110$

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Work, Energy, Power and Collision

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Perfectly Inelastic Collision

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$A$ scooter of mass $40 \ kg$ moving with a velocity of $4 \ m/s$ collides with another scooter of mass $60 \ kg$ moving with a velocity of $2 \ m/s$. After the collision,both scooters stick together. Find the loss in kinetic energy in $J$.

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